Question

bantuin tugas mm aku kak​

Answer 1

Jawaban:

11. 3x +2 = 0 -> x = -2/3

2x - 5 = 0 -> x= 5/2

f(-2/3) = 1

f(5/2) = 20

6x² -11 x- 10 = (3x +2 )(2x - 5) , misal sisa s(x) = ax +b

s(-2/3) = f (-2/3) --> -2/3 a + b = 1

s(5/2) = f(5/2) --> 5/2 a + b = 20

dikurangkan

(-2/3 - 5/2) a = 1 - 20

-19/6 a = -19

a= 6

5/2 a + b = 20

5/2 (6) + b = 20

15 + b = 20

b = 5

S(x) = ax + b

s(x)= 6x + 5

Penjelasan dengan langkah-langkah:

maaf cuman bisa nomor 11