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[6b 10c]
Bt(transpos matriks B) = [2a+2 a+4]
[a+8 3a-b]
2A = Bt jadi:
nilai a,b,c dari diperoleh dari:
u/ nilai a: 10 = 2a+2
-2a = 2 - 10
-2a = -8
a = 4
u/ nilai b: 6b = a+8
6b = 4+8
6b = 12
b = 2
u/ nilai c: 10c = 3a-b
10c = 3(4)-2
10c = 12-2
10c = 10
c = 1