Question

Bantuin no.8 dan 9!!!

Answer 1

PH = power of Hydrogen, menyatakan derajat keasaman

pH = -log [H⁺]
a. pH = - log 2 = - 0,3

b. pH = - log 10⁻² = 2

c. pH = - log 2.10⁻⁵ = 5 - log 2 = 5 - 0,3 = 4,7

d. pH = - log 8.10⁻⁴ = 4 - log 8 = 4 - log 2³ = 4 - 3 log 2 = 4 - 3.0,3 = 4 - 0,9 = 3,1

e. pH = - log 6.10⁻⁶ = 6 - log 6 = 6 - (log 2 + log 3) = 6 - (0,3+ 0,48) = 6 - 0,78 = 5,22

f. pH = - log 1,69.10⁻² = 2 - log 1,69 = 2 - 0,23 = 1,77