Question

Bantuin niih dikit lagi
pake cara juga

Answer 1

3log2 = m
(log2)/(log3) = m
log3 = (log2)/m

2log7 = n
(log7)/(log2) = n
log7 = n log2

14log54 = (log54)/(log14) = (log(3^3 . 2))/(log(7.2))
= ((log3^3)+(log2))/((log7)+(log2))
=((3log3)+(log2))/((log7)+(log2))
=((3((log2)/m)+(log2))/((nlog2)+(log2))
=log2((3/m)+1)/log2(n+1)
=((3/m)+1)/(n+1)
=(3+m)/(mn+m)