Question

Bantuin kawan , satu saja gpp​

Answer 1

Penjelasan dengan langkah-langkah:

7).

²log(3)= x and ³log(5)= y

²log(3). ³log(5)= ²log(5)= xy

= ⁴log(15)

= ²log(15)/²log(4)

= ²log(3 . 5) / ²log(2)²

= (²log(3) + ²log(5)) / 2

= (x + xy)/2

= ½ (x + xy)

.

8).

= (³log 36)² - (³log 4)² / (³log √12)

= (³log36-³log4)(³log36+³log4)/(³log 12^½)

= (³log(36/4))(³log(36.4))/(½ . ³log12)

= (³log9)(³log (144))/(½ . ³log 12)

= (³log3²)(³log (12²)/(½ . ³log 12)

= (2)(2. (³log 12))/(½)(³log 12)

= (2)(2)/(1/2)

= 4/(1/2)

= 4 . 2

= 8

Answer 2

Penyelesaian:

²log3=x ³log5=y

Sifat logaritma yg digunakan

x log a + x log b=x log ab

a log b×b log c=a log c

-----------------

Maka

²log 3 × ³log 5=²log5=xy

-----------------

⁴log 15

=2² log 3.5

=1/2(²log3+²log5)

=½(x+xy)