Jawab:
limit trigonometri bentuk 0/0, sifat :
i) lim (x->0) sin x/ x = lim (x->0) x/sin x = 1
ii) lim (x->0) cos x = 1
iii) lim (x->0) tan x/ x = lim (x->0) x/tan x = 1
Penjelasan dengan langkah-langkah:
lim (x - > 0) { x sin x } / { 1 - cos 2x }
* ubah 1 - cos 2x = 1 - ( 1 - 2 sin² x) = 2 sin² x
.
lim (x - > 0) { x sin x } / { 1 - cos 2x } = lim(x-> 0) { x sin x } / {2 sin² x }
= lim(x-> 0) (x . sin x) / 2 sin x. sin x)
= lim (x->0) 1/2 (x/sin x) (sin x / sinx)
= 1/2 (1)(1)
= 1/2
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Jawab:
limit trigonometri bentuk 0/0, sifat :
i) lim (x->0) sin x/ x = lim (x->0) x/sin x = 1
ii) lim (x->0) cos x = 1
iii) lim (x->0) tan x/ x = lim (x->0) x/tan x = 1
Penjelasan dengan langkah-langkah:
lim (x - > 0) { x sin x } / { 1 - cos 2x }
* ubah 1 - cos 2x = 1 - ( 1 - 2 sin² x) = 2 sin² x
.
lim (x - > 0) { x sin x } / { 1 - cos 2x } = lim(x-> 0) { x sin x } / {2 sin² x }
= lim(x-> 0) (x . sin x) / 2 sin x. sin x)
= lim (x->0) 1/2 (x/sin x) (sin x / sinx)
= 1/2 (1)(1)
= 1/2