Penjelasan dengan langkah-langkah:
Materi Lingkaran
3)
= 96/360 × 2 × 22/7 × 10,5
= 17,6 cm ( D )
4) Selisih Luas
= ( 3,14 × 25 × 25 ) - (3,14×24×24)
= 1962,5 - 1808,5
= 154 cm² ( A )
note : Hasil dalam pembulatan satuan terdekat
5)
BOC = (180-135)
= 45°
AOC/BOC = AC/BC
135/45 = AC/12
AC = 12×135/45
AC = 36 cm (C)
6)
LO.Abc - L∆Abc
= ( ½ × 3,14 × 5 × 5 ) - ( ½ × 8 × 6 )
= 39,25 - 24
= 15,25 cm²
L = ( ½× 3,14 × 4 × 4 ) + ( ½× 3,14 × 3 × 3)
= 25,12 + 14,13
= 39,25
= 39,25 - 15,25
= 24 cm² ( A )
7)
K = ½lingkaran
K = (πr)
132 = 22/7×π
π = 132 × 7/22
π = 42 cm ( B )
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Penjelasan dengan langkah-langkah:
Materi Lingkaran
3)
= 96/360 × 2 × 22/7 × 10,5
= 17,6 cm ( D )
4) Selisih Luas
= ( 3,14 × 25 × 25 ) - (3,14×24×24)
= 1962,5 - 1808,5
= 154 cm² ( A )
note : Hasil dalam pembulatan satuan terdekat
5)
BOC = (180-135)
= 45°
AOC/BOC = AC/BC
135/45 = AC/12
AC = 12×135/45
AC = 36 cm (C)
6)
LO.Abc - L∆Abc
= ( ½ × 3,14 × 5 × 5 ) - ( ½ × 8 × 6 )
= 39,25 - 24
= 15,25 cm²
L = ( ½× 3,14 × 4 × 4 ) + ( ½× 3,14 × 3 × 3)
= 25,12 + 14,13
= 39,25
= 39,25 - 15,25
= 24 cm² ( A )
7)
K = ½lingkaran
K = (πr)
132 = 22/7×π
π = 132 × 7/22
π = 42 cm ( B )