Materi : Trigonometri
BC = √[ 3² + 3² ] = √[ 2.3² ] = 3√2 cm { d. }
Tinggi Bendera
tan ° = de/sa
tan 45° = de/2,5
1 = de/2,5
de = 2,5 m
Maka Tinggi Bendera = 2,5 + 1,5 = 4 m { c. }
Kedalaman Jurang
tan 45° = de/10
1 = de/10
de = 10 m
Maka kedalaman jurang = 10 - 1,2 = 8,8 m { c. }
Tinggi gelas
sin ° = de/mi
sin 30° = 6/mi
½ = 6/mi
½ . mi = 6
mi = 12 cm { d. }
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
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Materi : Trigonometri
Soal Nomor 12
BC = √[ 3² + 3² ] = √[ 2.3² ] = 3√2 cm { d. }
Soal Nomor 13
Tinggi Bendera
tan ° = de/sa
tan 45° = de/2,5
1 = de/2,5
de = 2,5 m
Maka Tinggi Bendera = 2,5 + 1,5 = 4 m { c. }
Soal Nomor 14
Kedalaman Jurang
tan ° = de/sa
tan 45° = de/10
1 = de/10
de = 10 m
Maka kedalaman jurang = 10 - 1,2 = 8,8 m { c. }
Soal Nomor 15
Tinggi gelas
sin ° = de/mi
sin 30° = 6/mi
½ = 6/mi
½ . mi = 6
mi = 12 cm { d. }
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]