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Verified answer
1.katoda = 2H2O + 2e -->>> 2OH- + H2
anoda = 2O2- -->> O2 + 4e
2.
katoda = 2H2O + 2e -->>> 2OH- + H2
anoda = 2I- -->> I2 + 2e
3.
katoda = Cu2+ 2e -> Cu
anoda = 2H2O --->> 4H+ + O2 + 4e
4.
katoda = 2H2O + 2e -->>> 2OH- + H2
anoda = Au ->Au2+ 2e