Hasil pembagian
[tex] {x}^{2} + x - 12 = 0 \\ (x - 3)(x + 4) = 0 \\ \\ \frac{ {x}^{2} + x - 12}{(x + 4)} \\ \\ \frac{ (x - 3)(x + 4) }{(x + 4)} \\ \\ (x - 3 )\: (c)[/tex]
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Hasil pembagian
[tex] {x}^{2} + x - 12 = 0 \\ (x - 3)(x + 4) = 0 \\ \\ \frac{ {x}^{2} + x - 12}{(x + 4)} \\ \\ \frac{ (x - 3)(x + 4) }{(x + 4)} \\ \\ (x - 3 )\: (c)[/tex]