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proton Bi = 83; neutron = 209 - 83 = 126
jawaban: C
11. 11P = 2 8 1 ⇒ Gol. IA
12Q = 2 8 2 ⇒ Gol. IIA
13R = 2 8 3 ⇒ Gol. IIIA
19S = 2 8 8 1 ⇒ Gol. IA
20T = 2 8 8 2 ⇒ Gol. IIA
jawaban: E
13. Ar = [(% × A1) + (% × A2)] ÷ 100
= [(19 × 10) + (81 × 11)] ÷ 100 = 10,81
jawaban: E