~Peluang
n(s) = 6² = 36
n(A) = {(3,4) , (4,3) , (2,5) , (5,2) , (6,1) , (1,6)}
n(A) = 6
P(A) = n(A) / n(S)
P(A) = 6 / 36
P(A) = 1/6
#Backtoschool2019
Jawab:
2 buah dadu
= peluang kejadian = 36
peluang muncul dadu jumlah 7
= (1,6), (2,5), (3,4) (4,3), (5,2) (6,1) total = 6
peluang = 6/36
= 1/6 (C)
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~Peluang
n(s) = 6² = 36
n(A) = {(3,4) , (4,3) , (2,5) , (5,2) , (6,1) , (1,6)}
n(A) = 6
P(A) = n(A) / n(S)
P(A) = 6 / 36
P(A) = 1/6
#Backtoschool2019
Jawab:
2 buah dadu
= peluang kejadian = 36
peluang muncul dadu jumlah 7
= (1,6), (2,5), (3,4) (4,3), (5,2) (6,1) total = 6
peluang = 6/36
= 1/6 (C)