berarti
AE = CD = 13
CE x CD = 156
CE x 13 = 156
CE = 12
CB = √(12² + 5²) = √169 = 13 cm
luas ABCD =
(AB + CD) x CE))/2 =
(13+5 +13)x 12)/2 =
31 x 6 =
186
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berarti
AE = CD = 13
CE x CD = 156
CE x 13 = 156
CE = 12
CB = √(12² + 5²) = √169 = 13 cm
luas ABCD =
(AB + CD) x CE))/2 =
(13+5 +13)x 12)/2 =
31 x 6 =
186