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Verified answer
Mapel MatematikaBab Sudut Pusat dan Keliling
AOD = 64°
ABD merupakan sudut keliling dengan busur yg sama dgn sudut pusat AOD
ABD = 1/2 AOD
ABD = 32°
Perhatikan segitiga ABE
AEB + ABE + BAE = 180°
110° + 32° + BAE = 180°
142° + BAE = 180°
BAE = 38°
BAE = BAC merupakan sudut keliling dengan busur yg sama dengan sudut pusat BOC
BOC = 2 BAC
BOC = 76°
Verified answer
Aku juga Ada soal itu tapi lupa buku apakurang lebih gini kak;
∠AED = 180 - ∠AEB
∠AED = 180 - 110 = 70°
∠AED = 1/2 × (∠AOD + ∠BOC)
70 = 1/2 × (64 + ∠BOC)
64 + ∠BOC = 70 × 2
64 + ∠BOC = 140
∠BOC = 140 - 64
∠BOC = 76°