Question

Bantu ya no.2 .. kumohon tolong bngtt

Answer 1

Misalkan  ²log 6 = a dan ²log 3 = b dan  
²log 18 = ²log 6 + ²'log 3 = a+ b
(a² -b²) / (a+b) = (a+b)(a-b) / (a+b)
= a - b
=  ²log 6 - ²log 3 = ²log (6/3) = ²log2 = 1