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1 = 1 + 1
R R₂ R₃
1 = 1 + 1 = 1 + 2 = 3
R 12 6 12 12
R = 12 / 3 = 4 Ω
R₁, R₄, dan R (Hasil paralel R₂ dan R₃) diserikan
R Total = R₁ + R₄ + R
= 12 + 4 + 4
= 20 Ω
I = V
R
= 26 V
20 Ω
= 1,3 Ampere
Jadi, kuat arus yang mengalir pada rangkaian tsbt = 1,3 A (Tidak ada dlm pilihan)
14.) P = V²
R
= 24² V
(8 + 4) Ω
= 576 V
12 Ω
= 48 Watt
Jadi, daya listrik pada rangkaian tsbt = 48 W (B.)