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f '(x) = cos (3x² + 1) x (6x)
= 6x cos (3x² + 1)
semoga membantu ya :)
Maka,
Dengan dalil rantai:
Turunan dari:
sin x ⇒ cos x
3x²+1 ⇒ 6x
Sehingga,
f'(x) = sin'(3x²+1).(3x^2+1)'
f'(x) = cos(3x²+1).6x
f'(x) = 6x cos(3x²+1)