Question

Bantu ya besok ulangan soalnya, nomor 14-20 ya pakai cara :)

Answer 1

16. f(x)+ 2 = g(2x) + h(25)

log(x-3) + log 100 = log(2x-5) +log 25
100(x-3) = 25(2x-5)
4(x-3) = 2x - 5
4x - 2x = - 5 + 12
2x = 7
x = 3,5

17. soal burem gak jelas

18. sec ФФ = 1/cos Ф = cos⁻¹ Ф
ᵃlog sec Ф =  ᵃlog cos⁻¹Ф = -1 (ᵃlog cos Ф) =
ᵃlog sec Ф = - 1 (p)  = - p
 
19.  soal burem gak jelas

20. f(x) = T(x+5) + k(1/2x)
f(x) = ²log(x+5) + ²log(3-x)
f(x) = ²log(x+5)(3-x)
f '(x) = 0
(-2x-2)/(x+5)93-x). Ln 2 = 0
maka  - 2x - 2 = 0
x= -1

f(-1) = ²log (-1+5)(3+1) = ²log16 = 4