Jawaban:
v kerucut = ⅓πr²t
= ⅓ × 22/7 × 6 × 6 × 14
= 22 × 6 × 2 × 2
= 528 cm³
v ½ bola = ½ × 4/3 × π × r³
= ½ × 4/3 × 3,14 × 6 × 6 × 6
= 4 × 3,14 × 6 × 6
= 452,16 cm³
v bandul = 528 + 452,16
= 980,16 cm³
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Jawaban:
v kerucut = ⅓πr²t
= ⅓ × 22/7 × 6 × 6 × 14
= 22 × 6 × 2 × 2
= 528 cm³
v ½ bola = ½ × 4/3 × π × r³
= ½ × 4/3 × 3,14 × 6 × 6 × 6
= 4 × 3,14 × 6 × 6
= 452,16 cm³
v bandul = 528 + 452,16
= 980,16 cm³