7.
Sudut istimewa 30°
KL : LM = √3 : 2
KL : 20 = √3 : 2
2KL = 20√3
KL = 10√3 cm
Jawaban B
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9.
BD² = AD² + AB²
BD² = 8² + 8²
BD² = 64 + 64
BD² = 128
BD = √128
BD = 8√2 cm
Jawaban A
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7.
Sudut istimewa 30°
KL : LM = √3 : 2
KL : 20 = √3 : 2
2KL = 20√3
KL = 10√3 cm
Jawaban B
_________________
9.
BD² = AD² + AB²
BD² = 8² + 8²
BD² = 64 + 64
BD² = 128
BD = √128
BD = 8√2 cm
Jawaban A