Question

Bantu nomer 1 sampai nomer 5 yah, pliss

Answer 1

1. 3x - 12 = 0
3x = 12
x = 4
b. (x + 6) (x + 1) = 0
x = -6,-1
c. 3x² + 5x - 2 = 0
(3x - 1) (x + 2) = 0
x = 1/3,-2

2. 3x² + 3 = x² - 3x
2x² + 3x + 3 = 0
= bentuk pers kuadrat

3. α + β = 4
αβ = 2/3
pers kuadrat baru yang akar-akarnya (α + 2) dan (β + 2)
x² - (α + β + 4)x + αβ + 2(α + β) + 4 = 0
x² - (4 + 4)x + 2/3 + 2(4) + 4 = 0
x² - 8x + 38/3 = 0
3x² - 24x + 38 = 0

4. p + q = 5
pq = -1
pers kuadrat baru yang akar-akarnya 2p + 1 dan 2q + 1
x² - (2(p + q) + 2)x + 4pq + 2(p + q) + 1 = 0
x² - (2(5) + 2)x + 4(-1) + 2(5) + 1 = 0
x² - 12x + 7 = 0

5. m + n = 2
mn = 1/2
pers kuadrat baru yang akar-akarnya m + n dan mn
x² - (m + n + mn)x + m²n + mn² = 0
x² - (2 + 1/2)x + mn(m + n) = 0
x² - 5/2x + 1/2(2) = 0
x² - 5/2x + 1 = 0
2x² - 5x + 2 = 0