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f (0) = 0² - 4 . 0 - 12
= 0 - 0 - 12
= - 12
titik potong pada sumbuy (0 , - 12)
f(x) = x² - 4x + 3
0 = x² - 4x + 3
0 = (x - 1) (x - 3)
x - 1 = 0 atau x - 3 = 0
x = 1 atau x = 3
jadi pembuat nol adalah : x = 1 dan x = 3
f(x) = x² - 10x + 25 -----> a = 1 ; b = - 10 ; c = 25
persamaan sumbu simetri : x =
x =
=
= 5