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bar geometri
n = 5
a = 4
u5= 324
ar⁴ = 324
4 r⁴ =324
r⁴ = 81 = 3⁴
r= 3
Sn = a(rⁿ -1) / (r-1)
s5 = 4 (3⁵ -1)/(3-1)
s5 = 4(242)/(2) = 4(121) = 484
12.misal harga 1 kalng kue nastar = x
harga 1 kaleng kue keju = y
x = 2y substusikan ke 3x + 2y = 480.000 --> 3x + x = 480.000
4x = 480.000
x = 120.000
y = 1/2 x = 60.000
harga 2 kaleng nastar dan 3 kaleng kue keju
= 2x + 3y
= 2(120.000) + 3(60.000)
= 420.000