Penjelasan dengan langkah-langkah:
[tex]a) \: (p + 3 {)}^{2} = (p + 3)(p + 3) \\ = {p}^{2} + 3p + 3p + 9 \\ = {p}^{2} + 6p + 9 \\ \\ b)(3x - 2y {)}^{2} = (3x - 2y)(3x - 2y) \\ = 9 {x}^{2} - 6xy - 6xy + 4 {y}^{2} \\ = 9x {}^{2} - 12xy + 4 {y}^{2} \\ \\ c) ( \frac{2p}{3} {)}^{3} = ( \frac{2p}{3} {)}( \frac{2p}{3} {)}( \frac{2p}{3} {)} \\ = \frac{8 {p}^{3} }{27} \\ \\ d)( \frac{ - 2}{3 {x}^{2} } {)}^{2} = (\frac{ - 2}{3 {x}^{2} } {)}(\frac{ - 2}{3 {x}^{2} } {)} \\ = \frac{4}{9 {x}^{4} } [/tex]
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Penjelasan dengan langkah-langkah:
[tex]a) \: (p + 3 {)}^{2} = (p + 3)(p + 3) \\ = {p}^{2} + 3p + 3p + 9 \\ = {p}^{2} + 6p + 9 \\ \\ b)(3x - 2y {)}^{2} = (3x - 2y)(3x - 2y) \\ = 9 {x}^{2} - 6xy - 6xy + 4 {y}^{2} \\ = 9x {}^{2} - 12xy + 4 {y}^{2} \\ \\ c) ( \frac{2p}{3} {)}^{3} = ( \frac{2p}{3} {)}( \frac{2p}{3} {)}( \frac{2p}{3} {)} \\ = \frac{8 {p}^{3} }{27} \\ \\ d)( \frac{ - 2}{3 {x}^{2} } {)}^{2} = (\frac{ - 2}{3 {x}^{2} } {)}(\frac{ - 2}{3 {x}^{2} } {)} \\ = \frac{4}{9 {x}^{4} } [/tex]