[tex]3 \sqrt{5} + 4 \sqrt{5} - 6 \sqrt{3} + 2 \sqrt{3} = [/tex]
[tex](3 + 4) \sqrt{5} + ( - 6 + 2) \sqrt{3} = [/tex]
[tex]7 \sqrt{5} - 4 \sqrt{3} [/tex]
[tex] \frac{2}{3 + \sqrt{5} } = [/tex]
[tex] \frac{2}{3 + \sqrt{5} } · \frac{3 - \sqrt{5} }{3 - \sqrt{5} } = [/tex]
[tex] \frac{2(3 - \sqrt{5}) }{(3 + \sqrt{5} )(3 - \sqrt{5} )} = [/tex]
[tex] \frac{2(3 - \sqrt{5} )}{ {3}^{2} - { (\sqrt{5}) }^{2} } = [/tex]
[tex] \frac{6 - 2 \sqrt{5} }{9 - 5} = [/tex]
[tex] \frac{6 - 2 \sqrt{5} }{4} = [/tex]
[tex] \frac{3 - \sqrt{5} }{2} [/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
a
[tex]3 \sqrt{5} + 4 \sqrt{5} - 6 \sqrt{3} + 2 \sqrt{3} = [/tex]
[tex](3 + 4) \sqrt{5} + ( - 6 + 2) \sqrt{3} = [/tex]
[tex]7 \sqrt{5} - 4 \sqrt{3} [/tex]
b
[tex] \frac{2}{3 + \sqrt{5} } = [/tex]
[tex] \frac{2}{3 + \sqrt{5} } · \frac{3 - \sqrt{5} }{3 - \sqrt{5} } = [/tex]
[tex] \frac{2(3 - \sqrt{5}) }{(3 + \sqrt{5} )(3 - \sqrt{5} )} = [/tex]
[tex] \frac{2(3 - \sqrt{5} )}{ {3}^{2} - { (\sqrt{5}) }^{2} } = [/tex]
[tex] \frac{6 - 2 \sqrt{5} }{9 - 5} = [/tex]
[tex] \frac{6 - 2 \sqrt{5} }{4} = [/tex]
[tex] \frac{3 - \sqrt{5} }{2} [/tex]