Jawaban:
d. 5 - 2√6
Penjelasan dengan langkah-langkah:
[tex] \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} } [/tex]
[tex] = \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \times \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} - \sqrt{3} } [/tex]
[tex] = \frac{ \sqrt{2} \sqrt{2} + \sqrt{2} \times ( - \sqrt{3}) - \sqrt{3} \sqrt{2} - \sqrt{3} \times ( - \sqrt{ 3}) }{ (\sqrt{2} + \sqrt{ \\ 3}) ( \sqrt{2} - \sqrt{3}) } [/tex]
[tex] = \frac{ \sqrt{2} \sqrt{2} + \sqrt{2} \times ( - \sqrt{3}) - \sqrt{3} \sqrt{2} - \sqrt{3} \times ( - \sqrt{3})}{( \sqrt{2})^{2} - ( \sqrt{3})^{2} } [/tex]
[tex] = 5 - 2 \sqrt{6} \: (c)[/tex]
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Jawaban:
d. 5 - 2√6
Penjelasan dengan langkah-langkah:
[tex] \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} } [/tex]
[tex] = \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \times \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} - \sqrt{3} } [/tex]
[tex] = \frac{ \sqrt{2} \sqrt{2} + \sqrt{2} \times ( - \sqrt{3}) - \sqrt{3} \sqrt{2} - \sqrt{3} \times ( - \sqrt{ 3}) }{ (\sqrt{2} + \sqrt{ \\ 3}) ( \sqrt{2} - \sqrt{3}) } [/tex]
[tex] = \frac{ \sqrt{2} \sqrt{2} + \sqrt{2} \times ( - \sqrt{3}) - \sqrt{3} \sqrt{2} - \sqrt{3} \times ( - \sqrt{3})}{( \sqrt{2})^{2} - ( \sqrt{3})^{2} } [/tex]
[tex] = 5 - 2 \sqrt{6} \: (c)[/tex]
_____________________________________
Semoga membantu!!!
LearnWithBranly
TingkatkanPrestasimu