Jika a = 2 dan b = 3, Tentukan nilai dari
(a/b)⁴(b/a)⁻⁴(b/a)(ab)⁻¹ =
64/6561
Sederhanakanlah bentuk
[tex] \frac{{(x^ {\frac{1}{2}})}^{-3}{(y^{\frac{-2}{3}})}^{-2}}{x^{\frac{2}{3}} y^{\frac{-3}{2}}}[/tex] =
[tex] {(x^{-13} y^{17})}^{\frac{1}{6}} [/tex]
[tex]\\[/tex]
Rumus Perpangkatan :
(1/n ) = n⁻¹
(1/n⁻¹) = n¹
(-m)² = (-1)²m² = 1×m² = m²
(p⁻⁴) = 1/p⁴
(qᵐ)ⁿ = qᵐⁿ
sᵐ/sⁿ = sᵐ⁻ⁿ
Diketahui:
Ditanya:
(a/b)⁴(b/a)⁻⁴(b/a)(ab)⁻¹ ?
[tex] \frac{{(x^ {\frac{1}{2}})}^{-3}{(y^{\frac{-2}{3}})}^{-2}}{x^{\frac{2}{3}} y^{\frac{-3}{2}}}[/tex] ?
Dijawab :
Soal no 3a.
a = 2
a⁶ = 2⁶ = 64
b = 3
b⁸ = 3⁸ = 6561
untuk mencari jawaban tersebut terlebih dahulu disederhanakan dulu.
(a/b)⁴(a/b)⁴(a/b)⁻¹(1/(ab)) =
(a/b)⁴⁺⁴⁻¹ (1/(ab)) =
(a/b)⁷ (1/(ab)) =
a⁷/b⁷ × 1/(ab) =
a⁷/a × 1/(b⁷b) =
a⁶ /b⁸ =
Soal no 3b.
[tex] \frac{{(x^ {\frac{-3}{2}})}{(y^{\frac{4}{3}})}}{x^{\frac{2}{3}} y^{\frac{-3}{2}}}[/tex] =
[tex] x^{\frac{-3}{2}-\frac{2}{3}} y^{\frac{4}{3}-\frac{-3}{2}} [/tex] =
[tex] x^{\frac{-9}{6}-\frac{4}{6}} y^{\frac{8}{6}-\frac{-9}{6}} [/tex] =
[tex] x^{\frac{-13}{6}} y^{\frac{17}{6}} [/tex] =
Jadi
Kelas : 9 SMP
Mapel : Matematika
Bab : 1 - Bilangan Berpangkat dan Bentuk Akar
Kode Soal : 2
Kode kategori : 9.2.1
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Verified answer
Jika a = 2 dan b = 3, Tentukan nilai dari
(a/b)⁴(b/a)⁻⁴(b/a)(ab)⁻¹ =
64/6561
Sederhanakanlah bentuk
[tex] \frac{{(x^ {\frac{1}{2}})}^{-3}{(y^{\frac{-2}{3}})}^{-2}}{x^{\frac{2}{3}} y^{\frac{-3}{2}}}[/tex] =
[tex] {(x^{-13} y^{17})}^{\frac{1}{6}} [/tex]
[tex]\\[/tex]
Pembahasan :
Rumus Perpangkatan :
(1/n ) = n⁻¹
(1/n⁻¹) = n¹
(-m)² = (-1)²m² = 1×m² = m²
(p⁻⁴) = 1/p⁴
(qᵐ)ⁿ = qᵐⁿ
sᵐ/sⁿ = sᵐ⁻ⁿ
[tex]\\[/tex]
Diketahui:
Ditanya:
Jika a = 2 dan b = 3, Tentukan nilai dari
(a/b)⁴(b/a)⁻⁴(b/a)(ab)⁻¹ ?
[tex]\\[/tex]
Sederhanakanlah bentuk
[tex] \frac{{(x^ {\frac{1}{2}})}^{-3}{(y^{\frac{-2}{3}})}^{-2}}{x^{\frac{2}{3}} y^{\frac{-3}{2}}}[/tex] ?
Dijawab :
[tex]\\[/tex]
Soal no 3a.
a = 2
a⁶ = 2⁶ = 64
b = 3
b⁸ = 3⁸ = 6561
[tex]\\[/tex]
untuk mencari jawaban tersebut terlebih dahulu disederhanakan dulu.
[tex]\\[/tex]
(a/b)⁴(b/a)⁻⁴(b/a)(ab)⁻¹ =
(a/b)⁴(a/b)⁴(a/b)⁻¹(1/(ab)) =
(a/b)⁴⁺⁴⁻¹ (1/(ab)) =
(a/b)⁷ (1/(ab)) =
a⁷/b⁷ × 1/(ab) =
a⁷/a × 1/(b⁷b) =
a⁶ /b⁸ =
64/6561
[tex]\\[/tex]
Soal no 3b.
[tex] \frac{{(x^ {\frac{1}{2}})}^{-3}{(y^{\frac{-2}{3}})}^{-2}}{x^{\frac{2}{3}} y^{\frac{-3}{2}}}[/tex] =
[tex] \frac{{(x^ {\frac{-3}{2}})}{(y^{\frac{4}{3}})}}{x^{\frac{2}{3}} y^{\frac{-3}{2}}}[/tex] =
[tex] \frac{{(x^ {\frac{-3}{2}})}{(y^{\frac{4}{3}})}}{x^{\frac{2}{3}} y^{\frac{-3}{2}}}[/tex] =
[tex] x^{\frac{-3}{2}-\frac{2}{3}} y^{\frac{4}{3}-\frac{-3}{2}} [/tex] =
[tex] x^{\frac{-9}{6}-\frac{4}{6}} y^{\frac{8}{6}-\frac{-9}{6}} [/tex] =
[tex] x^{\frac{-13}{6}} y^{\frac{17}{6}} [/tex] =
[tex] {(x^{-13} y^{17})}^{\frac{1}{6}} [/tex]
[tex]\\[/tex]
Jadi
(a/b)⁴(b/a)⁻⁴(b/a)(ab)⁻¹ =
64/6561
[tex] \frac{{(x^ {\frac{1}{2}})}^{-3}{(y^{\frac{-2}{3}})}^{-2}}{x^{\frac{2}{3}} y^{\frac{-3}{2}}}[/tex] =
[tex] {(x^{-13} y^{17})}^{\frac{1}{6}} [/tex]
[tex]\\[/tex]
Pelajari lebih lanjut:
Detail Jawaban :
Kelas : 9 SMP
Mapel : Matematika
Bab : 1 - Bilangan Berpangkat dan Bentuk Akar
Kode Soal : 2
Kode kategori : 9.2.1