Question

bantu jawab, mau disetor besok, terimakasih.
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Answer 1

Penjelasan dengan langkah-langkah:

KESEBANGUNAN

Diketahui:

• AE = 10 cm
• EB = 5 cm
• EG = 9 cm
• BD = 21 cm
• AB = AE + EB = 10 cm + 5 cm = 15 cm
• BF ?
  => [tex]\sf \frac{AB}{EB} = \frac{BD}{BF} \\\sf \frac{15}{5} = \frac{21}{BF} \\\sf 15 \times BF = 5 \times 21\\\sf BF = \frac{105}{15} \\\sf \bf BF = 7 \ cm[/tex]
• AC ?
  => [tex]\sf \frac{AB}{EB} = \frac{AC}{EG} \\\sf \frac{15}{5} = \frac{AC}{9} \\\sf 5 \times AC = 15 \times 9\\\sf AC = \frac{135}{5} \\\sf \bf AC = 27 \ cm[/tex]

Setelahnya tentukan unsur layang-layang:

Layang - Layang ABCD

• Diagonal 1 ([tex]\sf d_1[/tex]) = BD = 21 cm
• Diagonal 2 ([tex]\sf d_2[/tex]) = AC = 27 cm

Layang - Layang BEFG

• Diagonal 1 ([tex]\sf d_1[/tex]) = BF = 7 cm
• Diagonal 2 ([tex]\sf d_2[/tex]) = EG = 9 cm

Ditanyakan:

Luas layang-layang ABCD dengan BEFG (luas gabungan) ?

Penyelesaian:

Rumus: [tex]\boxed {\sf \bf L = \frac{d_1 \times d_2}{2} }[/tex], maka:

Luas layang-layang ABCD
=> [tex]\sf \bf L = \frac{d_1 \times d_2}{2} \\\sf \bf L = \frac{21 \times 27}{2} \\\sf \bf L = \frac{567}{2} \\\underline {\boxed {\blue {\sf \bf L = 283 \frac{1}{2} \ cm^2 \iff \sf \bf 283,5 \ cm^2}}}[/tex]

Luas layang-layang BEFG
=> [tex]\sf \bf L = \frac{d_1 \times d_2}{2} \\\sf \bf L = \frac{7 \times 9 }{2}\\\sf \bf L = \frac{63}{2} \\\underline {\boxed {\blue {\sf \bf L = 31 \frac{1}{2} \ cm^2 \iff \sf \bf 31,5 \ cm^2}}}[/tex]

Luas Gabungan
=> 283,5 cm² + 31,5 cm² = [tex]\large {\underline {\boxed {\blue {\sf \bf 315 \ cm^2}}}}[/tex]

[tex] \large {\boxed {\blue {\star \:Answered  \: By: \:  \bold {sulkifli2018} \star} } } [/tex]