Question

Bantu jawab kak, 2 soal​

Answer 1

5). 3x = (7x - 60)°

3x - 7x = -60

-4x = -60

x = 60/4

x = 15°

n = (3x)°

= 3(15)

= 45°

Jadi, besar sudut n adalah 45°//

6). Komponen

• Segitiga siku-siku
• Trapesium sama kaki

____________

Segitiga siku-siku AEF (Rumus Teorema phytagoras berlaku!!), cari panjang AF

[tex] \sf \: AF = \sqrt{AE {}^{2} - EF {}^{2} } \\ \sf \: = \sqrt{ {5}^{2} - } 4 {}^{2} \\ = \sf\sqrt{25 - 16} \\ = \sqrt{9} \\ = 3[/tex]

______________

Trapesium sama kaki (ACDE), AC belum diketahui maka dicari panjang AC

Panjang AC = 11 + 3 + 3 = 17cm

______________

Segitiga ABC, Cari panjang AB yang belum diketahui menggunakan rumus Teorema Phytagoras

[tex] \sf \: AB = \sqrt{ AC {}^{2} - BC {}^{2} } \\ \sf \: = \sqrt{ {17}^{2} - {8}^{2} } \\ \sf = \sqrt{225} \\ = 15[/tex]

Keliling bangun ABCDE

Keliling = 15 + 8 + 5 + 11 + 5 = 44

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Answer 2

5) 3x = 7x - 60

(3 - 7)x = -60

-4x = -60

x = -60/-4

x = 60/4

x = 15/1

x = 15°

MAKA :

= (3 × 15)°

= 45°

6) P.AF :

= √5² - 4²

= √(5(5) - (4(4)

= √25 - 16

= √9

= √3²

= 3 CM

P.AC :

= (11 + 3 + 3)CM

= (14 + 3)CM

= 17 CM

P.AB :

= √17² - 8²

= √(17(17) - (8(8)

= √289 - 64

= √225

= √15²

= 15 CM

MAKA K :

K = (15 + 8 + 5 + 11 + 5)CM

= (23 + 16 + 5)CM

= (39 + 5)CM

= 44 CM

[tex]\boxed { \color{lime} \mathcal{INFINITE \: WORLD}}[/tex]