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2. 5(2p-q)-4(3p+2q) = 10p-5q-12p-8q = 10p-12p-5q-8q = -2p-13q
3. 4a²-25 = (2a+5)(2a-5)
4. 2x²-x-3 = (2x-3)(x+1)
= -12x^2 -15xy -8xy -10y^2
= -12x^2 -23xy -10y^2
2) untuk nomor 2 menjadi => -4 ( 3p + 2q ) -5 ( 2p -q )
= -12p -8q -10p + 5q
= -22p -3q
3) 4a^2 -25 = ( 2a + 5 ) ( 2a -5 )
jadi, hasil pemfaktoran dari 4a^2 -25 = ( 2a + 5 ) ( 2a -5 )
4) 2x^2 -x -3
2 x -3 = -6
jika dikali ( x ) = -6, jika ditambah ( + ) = -1
1 x 6
2 x -3 => karena jika dikali = -6, jika ditambah = -1
maka, 2x^2 -x -3
( 2x -3 ) ( x + 1 )
jadi, hasil pemfaktoran 2x^2 -x -3 = ( 2x -3 ) ( x + 1 )
lambang "^" = pangkat