PEMBAHASAN
Pythagoras
anggap ∆ABC siku di C
CD ⊥ AB
AB = BD + AD = 8 + 12 = 20 cm
Panjang BC
= √(BD × AB)
= √(8 × 20)
= √160
= √(16 × 10)
= 4√10 cm
Panjang AC
= √(AD × AB)
= √(12 × 20)
= √240
= √(16 × 15)
= 4√15 cm
Panjang CD
= √(BD × AD)
= √(8 × 12)
= √96
= √(16 × 6)
= 4√6 cm
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PEMBAHASAN
Pythagoras
anggap ∆ABC siku di C
CD ⊥ AB
AB = BD + AD = 8 + 12 = 20 cm
Panjang BC
= √(BD × AB)
= √(8 × 20)
= √160
= √(16 × 10)
= 4√10 cm
Panjang AC
= √(AD × AB)
= √(12 × 20)
= √240
= √(16 × 15)
= 4√15 cm
Panjang CD
= √(BD × AD)
= √(8 × 12)
= √96
= √(16 × 6)
= 4√6 cm