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y = x³-3x² fungsi turun y' < 0
y' = 3x²-6x < 0
3x(x-2) < 0
x=0 dan x = 2 maka HP = 0<x<2 D
13/
y = x³+3x²-9x+7 fungsi naik y'>0
y' = 3x²+6x-9>0 [ bagi dgn 3] menjadi x²+2x-3 > 0
(x-1)(x+3) > 0
x= 1 dan x = -3 HP = x< -3 atau x> 1