Jawab:
B. 65°
Penjelasan dengan langkah-langkah:
∠A1 = (6x - 5)°
∠B4 = (4x - 15)°
∠A2 = ∠B4 --> sudut dalam bersebrangan
∠A1 + ∠A2 = 180°
(6x - 5)° + (4x - 15)° = 180°
6x - 5 + 4x - 15 = 180
10x - 20 = 180
10x = 200
x = 20
∠A2 = (4x - 15)° = 4(20) - 15 = 80 - 15 = 65°
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Jawab:
B. 65°
Penjelasan dengan langkah-langkah:
∠A1 = (6x - 5)°
∠B4 = (4x - 15)°
∠A2 = ∠B4 --> sudut dalam bersebrangan
∠A1 + ∠A2 = 180°
(6x - 5)° + (4x - 15)° = 180°
6x - 5 + 4x - 15 = 180
10x - 20 = 180
10x = 200
x = 20
∠A2 = (4x - 15)° = 4(20) - 15 = 80 - 15 = 65°