Jawab:
Penjelasan dengan langkah-langkah:
trigonometri
__
tan A = - 3 = 3/ -1 = y/x, A di KD II
r² = x²+ y²
r² = (-1)² + (3)²
r² = 10
r= √10
cos A= x/r = - 1/√10
sin B = - 2/√10 , B di KD IV
cos B = √(1 - sin² B)
cos B = √(1 - 4/10)= √(6/10)= √6/ √10
cos A . cos B = ( -1 /√10)(√6 /√10)
cos A . cos B = - √6/ 10
cos A. cos B = - ¹/₁₀ √ 6
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Jawab:
Penjelasan dengan langkah-langkah:
trigonometri
__
tan A = - 3 = 3/ -1 = y/x, A di KD II
r² = x²+ y²
r² = (-1)² + (3)²
r² = 10
r= √10
cos A= x/r = - 1/√10
sin B = - 2/√10 , B di KD IV
cos B = √(1 - sin² B)
cos B = √(1 - 4/10)= √(6/10)= √6/ √10
cos A . cos B = ( -1 /√10)(√6 /√10)
cos A . cos B = - √6/ 10
cos A. cos B = - ¹/₁₀ √ 6