Materi : Trigonometri
Sin C = 3/10 . √10 = (3√10)/10 = de/mi
____________________________/
de = 3√10
mi = 10
sa² = mi² - de²
sa² = 10² - (3√10)²
sa² = 100 - 9(10)
sa² = 100 - 90
sa = √10
Gambar yang Terlampirkan
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
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Materi : Trigonometri
Sin C = 3/10 . √10 = (3√10)/10 = de/mi
____________________________/
de = 3√10
mi = 10
sa² = mi² - de²
sa² = 10² - (3√10)²
sa² = 100 - 9(10)
sa² = 100 - 90
sa = √10
Kesimpulan
Gambar yang Terlampirkan
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]