Question

Bantu dong dengan caranya !
Berapakah nilai n jika (n+4)!
per
(n+2)! = 42

Answer 1

(n + 4)! = 42
(n + 2)!

(n + 4) * (n + 3) * (n + 2)! = 42
               (n + 2)!

(n + 4)(n + 3) = 42

n² + 7n + 12 = 42
n² + 7n + 12 - 42 = 0
n² + 7n - 30 = 0
(n +10)(n - 3)

n + 10 = 0
n = -10

n - 3 = 0
n = 3

ambil yang positif.
jadi nilai n = 3