Question

Bantu dong... Butuh banget soalnya hehehehe.. Poin ya besar loh

Answer 1

Hukum kekekalan momentum

Pada arah sb X

mAvA = mavA'cos (-53) + mBvB'cos 37

vA = vA'cos 53 + vB'cos 37

5 = vA'. 3/5 + vB'. 4/5

3.vA' + 4.vB' = 25 .... (1)

Pada arah sb Y

0 = mavA'sin (-53) + mBvB'sin 37

0 = -vA'sin 53 + vB'sin 37

0 = -vA'. 4/5 + vB'. 3/5

-4.vA' + 3.vB' = 0 ....(2)

(2) kalikan 4

-16.vA' + 12.vB' = 0 ..... (3)

(1) kalikan 3

9.vA' + 12.vB' = 75 .... (4)

(4) kurangi dgn (3)

25.vA' = 75

vA' = 75/25 = 3 m/s

Jawaban. E