Jawaban:
1. D
2. B
3. B
4. A
5. C
6. B
7. B
8. –
9. B
10. B
11. A
12. A
13. B
Penjelasan dengan langkah-langkah:
PYTHAGORAS dan BANGUN DATAR
1. 20²+21²=29²
400+441 = 841
2. 6²+8²>9²
36+64 > 81
100 > 81
3. QR = √(17²–8²) = √(289–64) = √225 = 15 cm
4. d2 = 2×√(68/4)²–(30/2)² = 2×√(17²–15²)
d2 = 2×√(289–225) = 2×√64 = 2×8 = 16 cm
5. L1 : L2 = (10/5)² : (25/5)² = 4 : 25
6. dB = (64/4)√2 = 16√2 cm
7. j = √(12²–8²) = √(144–64) = √80 = 4√5 m
8. d.a = √(41²–9²) = √(1.681–81) = √1.600 = 40 cm
BC = √(40²–16²) = √(1.600–256) = √1.344 cm
BC = 8√21 cm
9. dB = √(20²+(200/20)² = √(400+100) = √500
dB = 10√5 cm
10. Luas Lingkaran = 22/7 × 28 × 28 = 616 × 4 = 2.464 cm²
besar sudut = 308/2.464 × 360° = 45°
11. K = 2 × 22/7 × 21 = 44 × 3 = 132 cm
L = 22/7 × 21² = 22 × 441/7 = 22 × 63 = 1.386 cm²
12. Luas = 3,14 × (62,8/3,14)²/4 = 314 cm²
13. dB = (60/4)√2 = 15√2 cm
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Jawaban:
1. D
2. B
3. B
4. A
5. C
6. B
7. B
8. –
9. B
10. B
11. A
12. A
13. B
Penjelasan dengan langkah-langkah:
PYTHAGORAS dan BANGUN DATAR
1. 20²+21²=29²
400+441 = 841
2. 6²+8²>9²
36+64 > 81
100 > 81
3. QR = √(17²–8²) = √(289–64) = √225 = 15 cm
4. d2 = 2×√(68/4)²–(30/2)² = 2×√(17²–15²)
d2 = 2×√(289–225) = 2×√64 = 2×8 = 16 cm
5. L1 : L2 = (10/5)² : (25/5)² = 4 : 25
6. dB = (64/4)√2 = 16√2 cm
7. j = √(12²–8²) = √(144–64) = √80 = 4√5 m
8. d.a = √(41²–9²) = √(1.681–81) = √1.600 = 40 cm
BC = √(40²–16²) = √(1.600–256) = √1.344 cm
BC = 8√21 cm
9. dB = √(20²+(200/20)² = √(400+100) = √500
dB = 10√5 cm
10. Luas Lingkaran = 22/7 × 28 × 28 = 616 × 4 = 2.464 cm²
besar sudut = 308/2.464 × 360° = 45°
11. K = 2 × 22/7 × 21 = 44 × 3 = 132 cm
L = 22/7 × 21² = 22 × 441/7 = 22 × 63 = 1.386 cm²
12. Luas = 3,14 × (62,8/3,14)²/4 = 314 cm²
13. dB = (60/4)√2 = 15√2 cm