Jawaban :
[tex]lim( \frac{ \sqrt{x + 2} - \sqrt{4x - 1} }{x - 1} )= - \frac{ \sqrt {3} }{2} \\ x = > 1[/tex]
[tex]lim( \frac{ {x}^{2} - 9 }{x - \sqrt{x + 6} }) = \frac{36}{6} \\x = > 3[/tex]
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Jawaban :
[tex]lim( \frac{ \sqrt{x + 2} - \sqrt{4x - 1} }{x - 1} )= - \frac{ \sqrt {3} }{2} \\ x = > 1[/tex]
[tex]lim( \frac{ {x}^{2} - 9 }{x - \sqrt{x + 6} }) = \frac{36}{6} \\x = > 3[/tex]