Question

bantu bang T__T ajhsjaaj​

Answer 1

Bangun Datar

[Persegi Panjang]

..

[tex]keliling = 2(panjang + lebar)[/tex]

[tex]panjang = \sqrt{diagonal {}^{2} - lebar {}^{2} } [/tex]

..

Penyelesaian Soal

[tex]keliling = 2(panjang + lebar)[/tex]

[tex]~~~~~~~~~~~~~~~=2( \sqrt{diagonal {}^{2} - lebar {}^{2} } + lebar)[/tex]

[tex]~~~~~~~~~~~~~~~=2( \sqrt{17 {}^{2} - 8 {}^{2} } + 8)[/tex]

[tex]~~~~~~~~~~~~~~~=2( \sqrt{289 - 64} + 8)[/tex]

[tex]~~~~~~~~~~~~~~~=2( \sqrt{225} + 8)[/tex]

[tex]~~~~~~~~~~~~~~~=2(15 + 8)[/tex]

[tex]~~~~~~~~~~~~~~~=2(23)[/tex]

[tex]~~~~~~~~~~~~~~~=\boxed{46 \: cm}[/tex]

..

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[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at}}\boxed{\colorbox{ccddff}{12/03/23}}[/tex]

Answer 2

menentukan panjang (Teorema Pyhtagoras)

p² = d² - l²

p² = 17² - 8²

p² = (17 × 17) - (8 × 8)

p² = 289 - 64

p² = 225

p = √225

p = 15 cm

Keliling

K = 2( p + l )

K = 2( 15 + 8 )

K = 30 + 16

K = 46 cm