Question

Bantu aku soal no 2-3 ya :)

Answer 1

Nomor 2
n(S) = 2 × 6
n(S) = 12

Soal A
Kejadian (K) = (2,G)(4,G)(6,G)
n(K) = 3

Peluang = n(K)/n(S)
Peluang = 3/12
Peluang = 1/4


Soal B
Kejadian (K) = (3,A)(5,A)
n(K) = 2

Peluang = n(K)/n(S)
Peluang = 2/12
Peluang = 1/6


Soal C
Kejadian (K) = (2,A)
n(K) = 1

Peluang = n(K)/n(S)
Peluang = 1/12



Nomor 3
n(S) = 6²
n(S) = 36

Kejadian (K) = (2,3)(2,5)(4,3)(4,5)(6,3)(6,5)
n(K) = 6

Peluang = n(K)/n(S)
Peluang = 6/36
Peluang = 1/6