..
[tex]S_{n}= \frac{n}{2} (2a+ (n - 1)b) [/tex]
U1 → U2 = ∆10
U2 → U3 = ∆5
U3 → U4 = ∆5
U4 → U5 = ∆5
[tex]S_{n}= \frac{n - 1}{2} (2(U_2)+ (n - 2)b_{(U_{2} \to U_{3})}) + U_1[/tex]
[tex]S_{16}= \frac{15}{2} (2(15)+ (16 - 2)5) + 5[/tex]
[tex]S_{16}= \frac{15}{2} (30+ 70) + 5[/tex]
[tex]S_{16}= \frac{15}{2} (100) + 5[/tex]
[tex]S_{16}= 750 + 5[/tex]
[tex]S_{16}= 755[/tex]
[tex]\begin{array}{lr}\texttt{Selamat Menunaikan Ibadah Puasa}\end{array}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 26 - 03 - 2023}}[/tex]
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Baris dan Deret
[Deret Aritmatika]
..
[tex]S_{n}= \frac{n}{2} (2a+ (n - 1)b) [/tex]
Penyelesaian Soal
U1 → U2 = ∆10
U2 → U3 = ∆5
U3 → U4 = ∆5
U4 → U5 = ∆5
..
[tex]S_{n}= \frac{n - 1}{2} (2(U_2)+ (n - 2)b_{(U_{2} \to U_{3})}) + U_1[/tex]
[tex]S_{16}= \frac{15}{2} (2(15)+ (16 - 2)5) + 5[/tex]
[tex]S_{16}= \frac{15}{2} (30+ 70) + 5[/tex]
[tex]S_{16}= \frac{15}{2} (100) + 5[/tex]
[tex]S_{16}= 750 + 5[/tex]
[tex]S_{16}= 755[/tex]
..
[tex]\begin{array}{lr}\texttt{Selamat Menunaikan Ibadah Puasa}\end{array}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 26 - 03 - 2023}}[/tex]