[tex]s = \sqrt{ {r}^{2} + {t}^{2} } = \sqrt{ {7}^{2} + {24}^{2} } \\ \sqrt{49 + 576} = \sqrt{625} = 25 \\ \\ luas \: permukaan \: bangun \\2 \times \pi \times r( \frac{s}{2} + r + t) \\ 2 \times \frac{22}{7} \times 7( \frac{25}{2} + 7 + 10) \\ 44(29,5) \\ 1.298 \: {cm}^{2} [/tex]
S = √7² + 24²
= √(7(7) + (24(24)
= √49 + 576
= √625
= √(25(25)
= √25²
= 25 CM
MAKA :
LP = (2(22/7(7(25/2 + 7/1 + 10/1)
= (2(22(7/7(25/2 + 14/2 + 20/2)
= (2(22(59/2)
= (44(59/2)
= (44 × 29,5)
= 1.298 CM²
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Verified answer
[tex]s = \sqrt{ {r}^{2} + {t}^{2} } = \sqrt{ {7}^{2} + {24}^{2} } \\ \sqrt{49 + 576} = \sqrt{625} = 25 \\ \\ luas \: permukaan \: bangun \\2 \times \pi \times r( \frac{s}{2} + r + t) \\ 2 \times \frac{22}{7} \times 7( \frac{25}{2} + 7 + 10) \\ 44(29,5) \\ 1.298 \: {cm}^{2} [/tex]
S = √7² + 24²
= √(7(7) + (24(24)
= √49 + 576
= √625
= √(25(25)
= √25²
= 25 CM
MAKA :
LP = (2(22/7(7(25/2 + 7/1 + 10/1)
= (2(22(7/7(25/2 + 14/2 + 20/2)
= (2(22(59/2)
= (44(59/2)
= (44 × 29,5)
= 1.298 CM²