Jawaban:
1.120 cm²
Penjelasan dengan langkah-langkah:
Lp = 2 × (pl + pt + lt)
LP = 2 × [(20 × 12) + (20 × 10) + (12 × 10)]
Lp = 2 × (240 + 200 + 120)
Lp = 2 × 560
Lp = 1.120 cm²
Luas = 2(p × l) + (p × t) + (l × t)
Luas = 2(20 × 12) + (20 × 10) + (12 × 10)
Luas = 2(240 + 200 + 120)
Luas = 2(560)
Luas = 1.120 cm²
Luas permukaan balok 1.120 cm²
[tex]\huge\tt\color{FF6666}{I}\color{FFB266}{t}\color{B2FF66}{s}\color{66FF66}{M}\color{66FFFF}{e}\color{66B2FF}{A}\color{6666FF}{l}\color{B266FF}{i}\color{FF66FF}{y}\color{FF66B2}{a}\color{FF9999}{♡}\color{FFCC99}{♡}[/tex]
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Jawaban:
1.120 cm²
Penjelasan dengan langkah-langkah:
Lp = 2 × (pl + pt + lt)
LP = 2 × [(20 × 12) + (20 × 10) + (12 × 10)]
Lp = 2 × (240 + 200 + 120)
Lp = 2 × 560
Lp = 1.120 cm²
Verified answer
Jawaban:
Luas permukaan balok
Luas = 2(p × l) + (p × t) + (l × t)
Luas = 2(20 × 12) + (20 × 10) + (12 × 10)
Luas = 2(240 + 200 + 120)
Luas = 2(560)
Luas = 1.120 cm²
Luas permukaan balok 1.120 cm²
[tex]\huge\tt\color{FF6666}{I}\color{FFB266}{t}\color{B2FF66}{s}\color{66FF66}{M}\color{66FFFF}{e}\color{66B2FF}{A}\color{6666FF}{l}\color{B266FF}{i}\color{FF66FF}{y}\color{FF66B2}{a}\color{FF9999}{♡}\color{FFCC99}{♡}[/tex]