Question

Błagam was HELP !!!

1. Oblicz Cp3 otrzymanego po zmieszaniu 20g 15% roztworu z 50g 30% roztworu.

Z góry dziękuję za pomoc :)

Answer 1

Cp1=15%

mr1=20g

ms1=Cp1*mr1/100%

ms1=15*20/100

ms1 = 3g

 

Cp2=30%

mr2=50g

ms2=Cp2*mr2/100%

ms2=30*50/100

ms2 = 15g

 

ms3=ms1+ms2=18g

mr3=mr1+mr2=70g

Cp3=ms3*100%/mr3

Cp3=18*100/70

Cp3 = 25,7%

 

Answer 2

Cp₁=15%

mr₁=20g

Cp=(ms*100%)/mr /*mr

Cp*mr=ms*100% /:100%

ms=(Cp*mr)/100%

ms₁=(Cp₁*mr₁)/100%

ms₁=(15%*20g)/100%=3g

ms₁=3g

Cp₂=30%

mr₂=50g

ms₂=(Cp₂*mr₂)/100%

ms₂=(30%*50g)/100%=15g

ms₂=15g

ms₃=ms₁+ms₂

ms₃=3g+15g=18g

mr₃=mr₁+mr₂

mr₃=20g+50g=70g

Cp₃=(ms₃*100%)/mr₃

Cp₃=(18g*100%)/70g=25,7%

Cp₃=25,7%

 

Odp. Stężenie procentowe powstałego roztworu wynosi 25,7%.