Skorzystamy ze wzorów:
[tex]\log_ab=\frac{1}{\log_ba}\\\log_ab+\log_ac=\log_a(bc)[/tex]
Zatem
[tex]\frac{1}{\log_67}+\frac{1}{\log_87}=\log_76+\log_78=\log_7(6*8)=\log_748 < \log_749=2[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Skorzystamy ze wzorów:
[tex]\log_ab=\frac{1}{\log_ba}\\\log_ab+\log_ac=\log_a(bc)[/tex]
Zatem
[tex]\frac{1}{\log_67}+\frac{1}{\log_87}=\log_76+\log_78=\log_7(6*8)=\log_748 < \log_749=2[/tex]