Odpowiedź:
L = 4*6 = 24
================
oraz
x² + ( 2√5)² = 6²
x² = 36 - 20 = 16
x = [tex]\sqrt{16} = 4[/tex]
Pole P = 2*2√5 * 4 = 16 √5 j²
==============================
Szczegółowe wyjaśnienie:
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Odpowiedź:
L = 4*6 = 24
================
oraz
x² + ( 2√5)² = 6²
x² = 36 - 20 = 16
x = [tex]\sqrt{16} = 4[/tex]
Pole P = 2*2√5 * 4 = 16 √5 j²
==============================
Szczegółowe wyjaśnienie: