fitridarna
A. 110 k =.....c = 5/5x{110-273} = 1 x (-163) = -163 c b. 22 k =......c = 5/5x{22-273} = 1 x {-251} = -251 c c. 402 k =....c = 5/5x{402-273} -= 1 x 129 = 129 c - 323 k =.....c = 5/5x{323-273} = 1 x 50 = 50 c
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khusnul351
makasih . jawaban nya sangat membantu :-)
b.22-273= -251
c.402-273= 129
d.323-273= 50
= 5/5x{110-273}
= 1 x (-163)
= -163 c
b. 22 k =......c
= 5/5x{22-273}
= 1 x {-251}
= -251 c
c. 402 k =....c
= 5/5x{402-273}
-= 1 x 129
= 129 c
- 323 k =.....c
= 5/5x{323-273}
= 1 x 50
= 50 c