Question

Bagaimana mengintegralkan sin3x.sin2x dx ?

Answer 1

Int - ( 1/2 cos(3x+2x) - 1/2 cos(3x-2x) )
- int ( 1/2 cos 5x - 1/2 cos x )
- ( 1/10 sin5x - 1/2 sinx ) +c
-1/10 sin5x + 1/2 sinx + c

Answer 2

Sin x sin y = [ cos (x-y) - cos (x+y) ]

= integral [ cos (x) - cos (5x) ] dx
= integral cos x - cos 5x dx
= [ sin x - cos 5x]