Bagaimana cara termudah untuk mencari =
inget pake cara klo mau caranya dibuku trus difoto juga gak apa yg penting caranya jelas dan masuk akal !!!
3²°°⁶(10²°¹³ + 5²°¹² x 2²°¹¹)
--------------------------------------
5²°¹²(6²°¹° + 3²°°⁹ x 2²°°⁸)
inget pake cara klo mau caranya dibuku trus difoto juga gak apa yg penting caranya jelas dan masuk akal !!!
3²°°⁶(10²°¹³ + 5²°¹² x 2²°¹¹)
--------------------------------------
5²°¹²(6²°¹° + 3²°°⁹ x 2²°°⁸)
Takamori37
}{5^{2012}[3^{2009}.2^{2008}](3^{1}\times2^{2}+1\times1)}\end{align}](https://tex.z-dn.net/?f=%24%5Cbegin%7Balign%7D%26%5Cfrac%7B3%5E%7B2006%7D%2810%5E%7B2013%7D%2B5%5E%7B2012%7D%5Ctimes2%5E%7B2011%7D%29%7D%7B5%5E%7B2012%7D%286%5E%7B2010%7D%2B3%5E%7B2009%7D%5Ctimes2%5E%7B2008%7D%29%7D+%5C%5C+%26%3D%5Cfrac%7B3%5E%7B2006%7D%28%285%5Ctimes2%29%5E%7B2013%7D%2B5%5E%7B2012%7D%5Ctimes2%5E%7B2011%7D%29%7D%7B5%5E%7B2012%7D%28%283%5Ctimes2%29%5E%7B2010%7D%2B3%5E%7B2009%7D%5Ctimes2%5E%7B2008%7D%29%7D+%5C%5C+%26%3D%5Cfrac%7B3%5E%7B2006%7D%285%5E%7B2013%7D%5Ctimes2%5E%7B2013%7D%2B5%5E%7B2012%7D%5Ctimes2%5E%7B2011%7D%29%7D%7B5%5E%7B2012%7D%283%5E%7B2010%7D%5Ctimes2%5E%7B2010%7D%2B3%5E%7B2009%7D%5Ctimes2%5E%7B2008%7D%29%7D+%5C%5C+%26%3D%5Cfrac%7B3%5E%7B2006%7D%5B5%5E%7B2012%7D.2%5E%7B2011%7D%5D%285%5E1%5Ctimes2%5E2%2B1%5Ctimes1%29%7D%7B5%5E%7B2012%7D%5B3%5E%7B2009%7D.2%5E%7B2008%7D%5D%283%5E%7B1%7D%5Ctimes2%5E%7B2%7D%2B1%5Ctimes1%29%7D%5Cend%7Balign%7D "$\begin{align}&\frac{3^{2006}(10^{2013}+5^{2012}\times2^{2011})}{5^{2012}(6^{2010}+3^{2009}\times2^{2008})} \\ &=\frac{3^{2006}((5\times2)^{2013}+5^{2012}\times2^{2011})}{5^{2012}((3\times2)^{2010}+3^{2009}\times2^{2008})} \\ &=\frac{3^{2006}(5^{2013}\times2^{2013}+5^{2012}\times2^{2011})}{5^{2012}(3^{2010}\times2^{2010}+3^{2009}\times2^{2008})} \\ &=\frac{3^{2006}[5^{2012}.2^{2011}](5^1\times2^2+1\times1)}{5^{2012}[3^{2009}.2^{2008}](3^{1}\times2^{2}+1\times1)}\end{align}")
}{5^{2012}[3^{2009}.2^{2008}](3^{1}\times2^{2}+1\times1)} \\ &=\frac{2^{2011}\times3^{2006}\times5^{2012}}{2^{2008}\times3^{2009}\times5^{2012}}\times\frac{5.4+1}{3.4+1} \\ &=\frac{2^3}{3^3}\times\frac{21}{13} \\ &=\frac{8}{27}\times\frac{21}{13} \\ &=\frac89\times\frac{7}{13} \\ &=\frac{56}{117}\end{align}](https://tex.z-dn.net/?f=%24%5Cbegin%7Balign%7D%26%3D%5Cfrac%7B3%5E%7B2006%7D%5B5%5E%7B2012%7D.2%5E%7B2011%7D%5D%285%5E1%5Ctimes2%5E2%2B1%5Ctimes1%29%7D%7B5%5E%7B2012%7D%5B3%5E%7B2009%7D.2%5E%7B2008%7D%5D%283%5E%7B1%7D%5Ctimes2%5E%7B2%7D%2B1%5Ctimes1%29%7D+%5C%5C+%26%3D%5Cfrac%7B2%5E%7B2011%7D%5Ctimes3%5E%7B2006%7D%5Ctimes5%5E%7B2012%7D%7D%7B2%5E%7B2008%7D%5Ctimes3%5E%7B2009%7D%5Ctimes5%5E%7B2012%7D%7D%5Ctimes%5Cfrac%7B5.4%2B1%7D%7B3.4%2B1%7D+%5C%5C+%26%3D%5Cfrac%7B2%5E3%7D%7B3%5E3%7D%5Ctimes%5Cfrac%7B21%7D%7B13%7D+%5C%5C+%26%3D%5Cfrac%7B8%7D%7B27%7D%5Ctimes%5Cfrac%7B21%7D%7B13%7D+%5C%5C+%26%3D%5Cfrac89%5Ctimes%5Cfrac%7B7%7D%7B13%7D+%5C%5C+%26%3D%5Cfrac%7B56%7D%7B117%7D%5Cend%7Balign%7D "$\begin{align}&=\frac{3^{2006}[5^{2012}.2^{2011}](5^1\times2^2+1\times1)}{5^{2012}[3^{2009}.2^{2008}](3^{1}\times2^{2}+1\times1)} \\ &=\frac{2^{2011}\times3^{2006}\times5^{2012}}{2^{2008}\times3^{2009}\times5^{2012}}\times\frac{5.4+1}{3.4+1} \\ &=\frac{2^3}{3^3}\times\frac{21}{13} \\ &=\frac{8}{27}\times\frac{21}{13} \\ &=\frac89\times\frac{7}{13} \\ &=\frac{56}{117}\end{align}")
2 votes
Thanks 1
More Questions From This User See All